Get information of linked site

Using Django Templates & Frontend
1

Hi I have single-project.html site which is showing some basic information about a product. In addition there is a link to a site where the user who posted the project and the user who wants to buy it can chat. In this second site I would like to add the project.image which is shown in single-project.html. Lastly the url 'conversation' project.owner.user.username leads to a url in a different app.
How can I handle that? Thanks

single-project.html

<div class="col-lg-8 col-md-8 col-sm-12 text-center mt-3">
      <img{{project.image.url}}"/> 
</div>
    <div class="col-lg-4 col-md-4 col-sm-12 mt-3">
      <h4 class="mt-3">Product-Information</h4>
      <div class="singleProject__info">
        {{project.describtion}}
        <hr>
        <div class="project__tags">                        
            <span class="tag tag--pill tag--main">
              <small>{{project.price}} €</small>
            </span>
            <span class="tag tag--pill tag--main">
              <small>{{project.location}}</small>
            </span>
        </div>
        <div>
          <a href="{% url 'conversation' project.owner.user.username %}">Send message</a>
        </div>
      </div>
2

It might be more helpful if you explicitly ask specific questions about these different topics. “How can I handle that?” is rather vague among the list of items you have above.

If you’re asking “How can I use the url tag to reference an external site”, the general answer to that is that you don’t.

From the docs of the url tag:

Returns an absolute path reference (a URL without the domain name) matching a given view and optional parameters.

I wouldn’t try to do it that way, I’d find some other way to manage those references. (Probably by storing them in a model and adding them to the context of the view in which they are going to be used.)