Hello,
I created a page that allows me to modify some parameters in a json file.
this page extends admin/base_site.html.
fot the moment, i have added this to the urls
path("admin/parameters/", views.all_parameters, name="admin-parameters"),
but I have to type the full url to access it’s quite annoying.
I would like this page to be easily accessible from the django admin menu but I can’t find how to do it.
This is what the idea I have in mind looks like
The only facility I see for doing this would be to extend the AdminSite.get_urls() method. You’ll probably also want to read the source code in django.contrib.admin.sites.AdminSite, especially the comments in the admin_view method.
it’s mandatory to replace the override the default admin site ?
As far as I can tell - without actually having done or tried this myself - yes.
It’s the AdminSite object that builds that page.
Thanks for your help !
I succeeded to do what i want.
I’m not sure it was make properly but it works.
If it can help someone, here’s what I did to get there
I’ve changed the default site like explanations here: Le site d’administration de Django | Documentation de Django | Django
And for my custom AdminSite i’ve made this:
class MyAdminSite(admin.AdminSite):
site_header = "Custom Administration"
def get_urls(self):
urls = super().get_urls()
my_urls = [path("settings/", self.admin_view(self.settings_view), name="settings")]
return my_urls + urls
def get_app_list(self, request, app_label=None):
app_list = super().get_app_list(request, app_label)
if app_label is None or app_label == 'general':
app_list.append(
{
"name": "General",
"app_label": "general",
"models": [
{
"name": "Settings",
"object_name": "settings",
"admin_url": "/admin/settings",
"view_only": True,
}
],
}
)
return app_list
def settings_view(self, request):
context = dict(self.each_context(request))
context['parameters'] = config.get_parameters()
return TemplateResponse(request, 'admin/settings/settings.html', context)
And the result:
