Resolving Template Syntax Error

Using Django Mystery Errors
1

Due to character limits that discord has I had to resort to hastebin. It has the error message. I am trying to get my ingredients to be updated one ingredient at a time. So that there is a link next to each of the ingredients. I am getting a template syntax error. I hear that django auto increments primary key values. I am looking for the default primary key for an object coming out of a listview. is there a way to find this so that I can name it in my template?

Link to code and error in hastebin due to discord limits Hastebin

2

Assuming there were no alterations in the process of copying that code to hastebin, the problem is that you have “smart quotes” around the url name and not apostrophes.

1 Like
3

I have a guess why this error occurs.
If you look at the 0001_initial.py file in the migrations folder, you will see that the primary key of the Ingredients model was created under the name “id”.

 operations = [
        migrations.CreateModel(
            name='Ingredient',
            fields=[
                ('id', models.BigAutoField(auto_created=True, primary_key=True, serialize=False, verbose_name='ID')),
                ('name', models.CharField(max_length=20)),
                ('quantity', models.FloatField()),
                ('unit', models.CharField()),
                ('price_per_unit', models.FloatField()),
            ],
        ),

This is why in your template you should reference PK of Ingredient model instance as “id”:

 <a target=“_blank” href=“{% url "ingredientupdate" item.id %}”>{{ item.name }}</a>
4

That is not an issue. Django uses the special name ‘pk’ as a synonym for the primary key of a model regardless of the field being used for the primary key.

See the docs for the pk lookup shortcut.

5

To be honest, I didn’t know there was a primary key synonym. So thanks for sharing this link.

I admit that my guess was wrong. But I’m glad that I learned something new from it.